The problem that Cal factored was a perfect square trinomial. The standard formula for a trinomial like this would be a2 + 2ab + b2= (a + b)2 and (a + b)2.
psquared-18p+81
Step 1: The middle term is the product of the square root of psquared and 81, which are p and 9, both multiplied by two, which equals 18p.
Step 2: Put the bases of a and c into parentheses, put a minus sign between them, raise them to the power of 2.
(p-9)squared
Thursday, May 5, 2011
Tuesday, May 3, 2011
The Daily Factor Exclusive: Morkesh Thanyooknead's E-mail to Princess Catherine
Dear Katie,
After dilligent study, and tedious leafing through the textbooks that you sent me in the post, I have designed your second ring. Here is what it will look like:
xsquared-x-6
Step 1: Put the last term into the top section of the diamond problem. Put the second term into the bottom section. Solve. In this case, the top would be -6 and the bottom -1. The two middle numbers would therefore be -3 and 2, because their product is the top number, and their sum is the bottom number.
Step 2: Input each middle number into this format: (x+/-number)
(x-3) (x+2)
Step 3: Find the number that would be used to get the value of the numbers to zero, and input them into the above format.
Answer: (x+3)(x-2)
After dilligent study, and tedious leafing through the textbooks that you sent me in the post, I have designed your second ring. Here is what it will look like:
xsquared-x-6
Step 1: Put the last term into the top section of the diamond problem. Put the second term into the bottom section. Solve. In this case, the top would be -6 and the bottom -1. The two middle numbers would therefore be -3 and 2, because their product is the top number, and their sum is the bottom number.
Step 2: Input each middle number into this format: (x+/-number)
(x-3) (x+2)
Step 3: Find the number that would be used to get the value of the numbers to zero, and input them into the above format.
Answer: (x+3)(x-2)
Sincerely,
Morkesh
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